Respuesta :

Rewrite the expression as follows.

[tex](g\circ f)(x)=g(f(x))[/tex]

Substitute the value of f(x) into the value of x in g(x).

[tex]\begin{gathered} g(f(x))=g(2x^2-x+12) \\ =-3(2x^2-x+12)-4 \end{gathered}[/tex]

Simplify the expression by distributing -3 to the trinomial and then combine like terms, -36 and -4.

[tex]\begin{gathered} g(f(x))=-3(2x^2)-3(-x)-3(12)-4 \\ =-6x^2+3x-36-4 \\ =-6x^2+3x-40 \end{gathered}[/tex]

Thus, the value of the expression is as follows.

[tex](g\circ f)(x)=-6x^2+3x-40[/tex]

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