Respuesta :

Let:

[tex]\begin{gathered} (x1,y1)=(2,30) \\ (x2,y2)=(8,48) \end{gathered}[/tex]

The slope m of the line is:

[tex]m=\frac{y2-y1}{x2-x1}=\frac{48-30}{8-2}=\frac{18}{6}=3[/tex]

Using the point-slope equation:

[tex]\begin{gathered} y-y1=m(x-x1) \\ y-30=3(x-2) \end{gathered}[/tex]

Solve for y:

[tex]\begin{gathered} y-30=3x-6 \\ y=3x+24 \\ \end{gathered}[/tex]

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