Question

the slope to determine if lines PQ and RS are parallel, perpendicular, or neither. P (0, -2), Q (0,7), R (3,-5), S (6,-5) Slope of PQ Slope of RS Types of Lines

Answer 1

Given the points :

$\begin{gathered} P=(0,-2) \\ Q=(0,7) \\ R=(3,-5) \\ S=(6,-5) \end{gathered}$

The slope of PQ will be :

$slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{7-(-2)}{0-0}=\frac{9}{0}$

As the division by zero is undefined, PQ will vertical

The slope od RS will be :

$slope=\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1}=\frac{-5-(-5)}{6-3}=\frac{-5+5}{3}=\frac{0}{3}=0$

So, the line RS is horizontal

So, the lines PQ and RS are perpendicular