Question

a bag contains 9 red, 7 blue, and 4 yellow marble is chosen at random from the bag, what is the probability that it is not yellow in a fraction

Answer 1

As per given by the question,

There are given that, 9 red marble, 7 blue marbles, and 4 yellow marbles contain in bag.

Now,

From the given bag;

Total number of marble contains in bag is,

9+7+4=20.

Then,

The probability that chosen yellow marble,

$P=\frac{number\text{ of yellow marble in a bag }}{\text{total numbers of marble in a bag}}$

So,'

There are yellow marbles is 4 and total number of marbles is 20 in a bag.

Then, the probability is;

$\begin{gathered} P=\frac{number\text{ of yellow marble in a bag }}{\text{total numbers of marble in a bag}} \\ P=\frac{4}{20} \\ P=\frac{1}{5} \end{gathered}$

Now,

The probability that it is not yellow;

So,

$\begin{gathered} P(\text{not yellow)=1-probability(yellow)} \\ P(\text{not yellow)=}1-\frac{1}{5} \\ P(\text{not yellow)=}\frac{5-1}{5} \\ P(\text{not yellow)=}\frac{4}{5} \end{gathered}$

The probability that it is not a yellow marble is,

$\frac{4}{5}$

Hence, the option D is correct, that means

$\text{option (D)=}\frac{4}{5}$