Given the function
[tex]5x^2-2x-3=0[/tex]
We use the general formula for quadratic equations.
Where: a = 5, b = -2 and c = -3
[tex]x=\frac{-(-2)\pm\sqrt[]{(-2)^2-4(5)(-3)}}{2(5)}[/tex]
And solve
[tex]\begin{gathered} x=\frac{2\pm\sqrt[]{4+60}}{10} \\ x=\frac{2\pm\sqrt[]{64}}{10} \\ x=\frac{2\pm8}{10} \end{gathered}[/tex]
Separate the solutions
[tex]\begin{gathered} x=\frac{2+8}{10}=\frac{10}{10}=1 \\ and \\ x=\frac{2-8}{10}=\frac{-6}{10}=-\frac{3}{5} \end{gathered}[/tex]
Answer: B. x = 1, -3/5
