Answer:
The y-intercept is (0, 1)
The range of the function is (-∞, 1] U [1, ∞)
Explanation:
The graph of f(x) = sec(x) is the following
Then, the y-intercept is the point where the graph crosses the y-axis, so this point is (0, 1).
The asymptotes occur at x = 1/2π, x = 3/2π, and so on.
The range is the set of values that the variable y can take. In this case, y can be any number except the numbers between -1 and 1, so the range is (-∞, 1] U [1, ∞).
Finally, the graph never crosses the x-axis, so it doesn't have an x-intercept.
Then, the answers are
The y-intercept is (0, 1)
The range of the function is (-∞, 1] U [1, ∞)
