Question

5. Find the length of a rectangle whose width is 4xy and whose area is16xy² + 24x²y.a. 10xyb. 4y + 6xc. 12y + 20xd. 24xye. 10y + 10x

Answer 1

The area of a rectangle is:

$Area=length*width$

Solve length in the equation above:

$length=\frac{Area}{width}$

Use the given information to find the length:

$\begin{gathered} length=\frac{16xy^2+24x^2y}{4xy} \\ \\ length=\frac{xy(16y+24x)}{4xy} \\ \\ length=\frac{16y+24x}{4} \\ \\ length=\frac{16}{4}y+\frac{24}{4}x \\ \\ length=4y+6x \end{gathered}$

Then, the length of the rectangle is 4y+6x

Answer: b.