Question

In the year 2010, Xavier's car had a value of $22,000. When he bought the car in 2006 he paid $28,500. If the valueof the car depreciated linearly, what was the annual rate of change of the car's value? Round your answer to thenearest hundredth if necessary.

Answer 1

Solution

For this case we know that the value at 2010 is 22000$ and in 2006 was 28500$

Then we can find the rate of change on this way

$\frac{28500-22000}{2010-2006}=1625$

Then we can conclude that the answer is:

$ 1625 per year