Given the following question:
[tex]\begin{gathered} n=10 \\ r=5 \\ \frac{10!}{(5!(10-5)!)} \\ \frac{10!}{(5!(10-5)!)}=\frac{10\times9\times8\times7\times6}{5!} \\ =\frac{10\times9\times8\times7\times6}{5!} \\ =\frac{10\times9\times8\times7\times6}{5!}=252 \\ =252 \end{gathered}[/tex]Your answer is 252.