Question

To approach the runway, a small plane must begin at 9°descent starting from a height of 1,125 ft above theground. How many feet from the runway is the airplaneat the start of this approach? Round the distance to thenearest foot.

Answer 1

C

Since the small plane must begin its approximation at 9º descent

The plane is at 1,125 ft high.

Then let's calculate.

We have an elevation, and this is calculated by the sine of 9. We can see that the upper 9º is a congruent angle to a lower one.

Therefore, we can calculate the hypotenuse (the distance from the airplane to the runway) like this

$\begin{gathered} x\text{=}\frac{1125}{\sin (9)} \\ x=7191.5 \\ x\approx7192\text{ ft} \end{gathered}$