Using the kinematics formula,
[tex]\begin{gathered} v=u+at \\ u=60m/s^{} \\ a=-9.8m \\ v=0\text{ m/s} \\ 0=60-9.8t \\ -60=-9.8t \\ t=\frac{-60}{-9.8} \\ t=6.12244897959\approx6\text{ secs} \end{gathered}[/tex]
The ball will reach the maximum height at 6 seconds and also takes another 6 seconds to come down after reaching its maximum height.
total time taken = 6 + 6 = 12 seconds
