For this type of problem we add up the individual areas of each region, in this case we have 3 squares and 2 triangles, the squares have sides of 6 m of lenght and the triangles have a base of 6 m and a height of 4 m.
Recalling that the area of a square is sides* side, the area of each square is
[tex]A_s=36m^2_{}[/tex]and the area of a triangle is
[tex]A_t=\frac{bh}{2}=\frac{6m\cdot4m}{2}=\frac{24}{2}m^2=12m^2[/tex]Finally we add up the areas:
[tex]A=3A_s+2A_t=3(36m^2)+2(12m^2)=132m^2[/tex]Answer: The area is 132m^2.