To solve:
[tex](\frac{2^2x^2}{xy^2})^2[/tex]when x= 3 and y =2
simply substitute the values in the expression and then evaluate
[tex](\frac{2^2.3^2}{3.2^2})^2[/tex][tex]=(\frac{4\times9}{3\times4})^2[/tex][tex]=(\frac{36}{12})^2[/tex][tex]=3^2[/tex][tex]=9[/tex]