Question

Find all critical points for the function. Separate multiple answers with a comma

Answer 1

We have the next function

$f(x)=-10x^2-160x+9$

First we need to obtain the first derivate

$f^{\prime}(x)=-20x-160$

Then we find the value of x when the derivate is 0

$\begin{gathered} -20x-160=0 \\ -20x=160 \\ x=\frac{160}{-20} \\ x=-8 \end{gathered}$

The critical point of the function is x=-8