Question

in the following exercise, use a calculator to approximate the value to the nearest Foot. The baseball diamond is a square, 90 feet on a side. How far (in ft) must a catcher throw the ball to throw out a runner stealing second base?

Answer 1

Answer:

127 ft

Explanation:

The diagonal form a right triangle with two of the sides of 90ft. This means that we can use the Pythagorean theorem, where the legs are 90 ft. So, we can find the measure of the diagonal as:

$\sqrt[]{90^2+90^2}=\sqrt[]{8100+8100}=\sqrt[]{16200}=127.27\approx127\text{ ft}$

Therefore, the catcher must throw the ball 127 ft. because this is the distance from the catcher to the 2nd base.