given that x<35. which COULD be the area of this triangle

since x < 35
let us use x = 34
Using herons formular
[tex]\begin{gathered} A=\sqrt[]{p(p-a)(p-b)(p-c)} \\ p=\frac{35+34+22}{2}=\frac{91}{2}=45.5 \\ A=\sqrt[]{45.5(45.5-35)(45.5-34)(45.5-22)} \\ A=359.3215 \\ \end{gathered}[/tex]The Area of the triangle can't go above 359.3215 since x is less than 35 we used the closest number of x that is less than 35. The area will be 335 cm squared