In order to calculate the volume and density of the steel given in the table 3, consider that the shape of the material is a cylinder. Then, the volume is given by:
[tex]V=\pi r^2h[/tex]
where r is the radius of the base and h the height.
In this case, you have:
r = diameter/2 = 1.3 cm/2 = 0.65cm = 0.0065 m
h = 5 cm = 0.05 m
π = 3.14
Replace the previous values into the formula for V and simplify:
[tex]V=(3.14)(0.0065m)^2(0.05m)\approx0.0000063m^3[/tex]
Hence, the volume, in m^3 of the given steel is approximately 0.0000063m^3.
The density is given by:
[tex]\text{density}=\frac{\text{mass}}{\text{volume}}[/tex]
In this case, you have:
mass = 50.7 g = 0.0507 kg
volume = V = 0.0000063m^3
[tex]\text{density}=\frac{0.0507kg}{0.0000063m^3}\approx7639.44\frac{kg}{m^3}[/tex]
Hence, the density of the given steel is approximately 7639.44 kg/m^3
