Answer
Given:
BD bisects AE
∠A ≅ ∠E
To prove that:
[tex]\Delta ABC\cong\Delta EDC[/tex]
Consider the figures:
Since BD bisects AE, it follows that CA ≅ CE and CBA ≅ CD. (Two sides)
Therefore, the other side of the triangles AB ≅ ED
∠A ≅ ∠E, that is ∠CAB ≅ ∠CED
∴ ΔABC ≅ ΔEDC
