[tex]\begin{gathered} \text{slope}=m=\frac{y_2-y_1}{x_2-x_1} \\ \end{gathered}[/tex]
Therefore,
4.
[tex]\begin{gathered} (-1,3)(4,-7) \\ \text{slope}=\frac{-7-3}{4+1} \\ \text{slope}=\frac{-10}{5}=-2 \end{gathered}[/tex]
5.
[tex]\begin{gathered} (3,2)(6,5) \\ \text{slope}=\frac{5-2}{6-3} \\ \text{slope}=\frac{3}{3} \\ \text{slope}=1 \end{gathered}[/tex]
