[tex]\begin{gathered} \text{Volume of a cone = }\frac{1}{3}\times\pi\times r^2\times h \\ r=\text{ 4in} \\ h\text{ = 9in} \\ \pi=\text{ 3.14} \end{gathered}[/tex][tex]V\text{ = }\frac{1}{3}\times3.14\times4^2\times9[/tex][tex]\begin{gathered} V\text{ = }\frac{452.16}{3} \\ V=150.72inch^3 \end{gathered}[/tex]
volume of cone approximately is 151 cubic inch