We can see from the picture of the question that the error in solving this system of linear equations was that when the second equation was multiplied by -4. We need to multiply the whole equation, including the right side of the equation. We can see that:
[tex]-4\cdot((x-2y)=-13)=-4\cdot x+(-4)\cdot(-2y)=-4\cdot(-13)[/tex]
And the result must be:
[tex]-4x+8y=52[/tex]
And the second equation was: -4x + 8y = -13 (this is not correct.)
Therefore, the right side of the equation was not multiplied by -4 (this was the error.) (First option.)
The correct answer is:
Substituting this value in the first equation, we can, then, find the value for x:
[tex]4x+3(\frac{60}{11})=8\Rightarrow4x+\frac{180}{11}=8\Rightarrow4x=8-\frac{180}{11}[/tex]