Respuesta :
Answers: 1:B, 2:450
How-To:
Using the formula for area on the bottom of the can, (pi*r^2) you can then multiply by the amount of height missing, which is 4.
Since it was originally 10, you subtract 4 in order to get 6.
That's how to get 4.
Now, plug in pi*r^2 into a calculator (or if you must work it out, radius, r, is 10, so 10*10 is 100. 100*3.14159265 is 314.159265
Now multiply 314 by the height missing (4) to get approximately 1257.
Now for number 2.
It says it is dilated by a scale factor of 1:3 (from 1350). That means that it was made smaller, (that's what dilated means) by 3 for every 1. So take 1350 and divide it by 3 to get 450
How-To:
Using the formula for area on the bottom of the can, (pi*r^2) you can then multiply by the amount of height missing, which is 4.
Since it was originally 10, you subtract 4 in order to get 6.
That's how to get 4.
Now, plug in pi*r^2 into a calculator (or if you must work it out, radius, r, is 10, so 10*10 is 100. 100*3.14159265 is 314.159265
Now multiply 314 by the height missing (4) to get approximately 1257.
Now for number 2.
It says it is dilated by a scale factor of 1:3 (from 1350). That means that it was made smaller, (that's what dilated means) by 3 for every 1. So take 1350 and divide it by 3 to get 450
Answer:
Part 1) Option B [tex]1,257\ cm^{3}[/tex]
Part 2) The volume of the resulting cone is [tex]50\ cm^{3}[/tex]
Step-by-step explanation:
Part 1)
Find the volume of the can
The volume of the cylinder (can) is equal to
[tex]V=\pi r^{2}h[/tex]
we have
[tex]r=10\ cm[/tex]
[tex]h=10\ cm[/tex]
substitute
[tex]V=\pi (10^{2})(10)=1,000 \pi\ cm^{3}[/tex]
Remember that
For [tex]h=10\ cm[/tex] subtends a volume of [tex]V=1,000 \pi\ cm^{3}[/tex]
so
by proportion
Find the volume for [tex]h=10-6=4\ cm[/tex]
[tex]\frac{1,000\pi }{10}=\frac{x}{4}\\ \\x=1,000\pi *4/10\\ \\x=400\pi \\ \\x=1,257\ cm^{3}[/tex]
Part 2)
we know that
If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube
Let
z----> the scale factor
x-----> the volume of the resulting cone
y-----> the volume of the original cone
so
[tex]z^{3}=\frac{x}{y}[/tex]
in this problem we have
[tex]z=1/3[/tex]
[tex]y=1,350\ cm^{3}[/tex]
substitute and solve for x
[tex](1/3)^{3}=\frac{x}{1,350}[/tex]
[tex](1/27)=\frac{x}{1,350}[/tex]
[tex]x=1,350*(1/27)=50\ cm^{3}[/tex]