A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the secondroll? Write your answer as a reduced fraction or whole number.Your answer is :

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The probability of the die showing any given output is 1/6.

Then, the probability of showing a 1 on the first turn is 1/6.

On the second turn, the probability of showing an even number is 1/2 because half of the output numbers are even.

To find the probability of showing a 1 on the first turn and an even number on the second turn, multiply the probabilities of each event:

[tex]\frac{1}{6}\times\frac{1}{2}=\frac{1}{12}[/tex]

Therefore, the probability of showin a 1 on the first roll and an even number in the second roll is 1/12.

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