Question

write the equation of the line perpendicular to 3x-4y=5 and passing through the points (0,-3) write the equation in standard form.

Answer 1

$3x-4y=5\rightarrow4y=3x-5\rightarrow y=\frac{3}{4}x-\frac{5}{4}$

therefore the new slope is -4/3. So we get

$y=-\frac{4}{3}x-3$