We have to find the equation of the line that pass through (-1,-1) and (2,8).
We can start by calculating the slope as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-(-1)}{2-(-1)}=\frac{9}{3}=3[/tex]Then, we can take a point and the calculated slope and write the equation in slope-point form and then rearrange it:
[tex]\begin{gathered} y-y_1=m(x-x_0) \\ y-8=3(x-2) \\ y=3x-3\cdot2+8 \\ y=3x-6+8 \\ y=3x+2 \end{gathered}[/tex]Answer: y = 3x+2
