Respuesta :

We have the series: 3, 4.5, 6, 7.5, 9, ...

First, we have to find the relation between the terms.

We see that, if we substract from one term, the previous term, we get a constant:

[tex]a_n-a_{n-1}=1.5[/tex]

This is the common difference, so we can write:

[tex]a_n=a_{n-1}+1.5[/tex]

This is the recursive formula.

We have to find the explicit formula, that only depends on n.

To do so, we start by writing:

[tex]\begin{gathered} a_1=3 \\ a_2=4.5=3+1.5_{} \\ a_3=6=4.5+1.5=3+1.5+1.5=3+2\cdot1.5 \\ a_4=3+3\cdot1.5 \\ a_n=3+(n-1)\cdot1.5 \end{gathered}[/tex]

Then, the explicit formula for the nth term is:

[tex]a_n=3+(n-1)\cdot1.5=1.5+1.5n=1.5(1+n)[/tex]

Any of this expression is valid.

RELAXING NOICE
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