Question

What is the equation of the following line? Be sure to scroll down first to seeall answer options.(-4, 8)(0,0)10A. y=zxB. y=-*O C. y=-2xO D. y = xE. y = 4xF. y = 2x

Answer 1

slope of line is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Where,

$\begin{gathered} m=\text{slope} \\ (x_1,y_1)=\text{first point.} \\ (x_2,y_2)=\text{second point.} \end{gathered}$

So, slope of line is:

$\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{8-0}{-4-0} \\ m=-\frac{8}{4} \\ m=-2 \end{gathered}$

General equation of line.

$y=mx+c$$\begin{gathered} at\text{ point (0,0)} \\ y=mx+c \\ 0=m(0)+c \\ c=0 \end{gathered}$

Then equation of line is:

$\begin{gathered} y=mx+c \\ y=-2x+0 \\ y=-2x \end{gathered}$