Respuesta :
0=ax^2+bx+c
we got
1=2x^2+7x
minus 1 both sides
0=2x^2+7x-1
a=2
b=7
c=-1
b^2-4ac=
7^2-4(2)(-1)=
49+8=
57
we got
1=2x^2+7x
minus 1 both sides
0=2x^2+7x-1
a=2
b=7
c=-1
b^2-4ac=
7^2-4(2)(-1)=
49+8=
57
Answer:
The value of b² - 4ac is 57
Step-by-step explanation:
To find the value of b² - 4ac in the equation;
1 = 2x² + 7x
We need to first rearrange the equation
2x² + 7x - 1 = 0 -----------------------------------------------------------------(1)
The general form of quadratic equation is;
ax² + bx + c = 0 ---------------------------------------------------------------(2)
Comparing equation (1) and equation (2)
a =2 b=7 and c= -1
We are ask to find b² - 4ac
Substitute the values into b² - 4ac
b² - 4ac = 7² -(4)(2)(-1)
=49 +8
=57
Therefore, the value of b² - 4ac is 57