Given:
[tex]\begin{gathered} m\angle B=115^0 \\ a=8\text{feet} \\ c=13\text{feet} \end{gathered}[/tex]
Let us now sketch the triangle ABC
The formula to obtain the area(A) of the triangle is,
[tex]A=\frac{1}{2}ac\sin B[/tex]
Therefore,
[tex]\begin{gathered} A=\frac{1}{2}\times8\times13\times\sin 115^0 \\ A=4\times13\times\sin 115^0=52\sin 115^0=47.128005feet^2\approx47.13feet^2(2\text{ decimal places)} \end{gathered}[/tex]
Hence, the area of the triangle ABC is
[tex]47.13\text{feet}^2[/tex]
The correct option is Option 1.
