Given:
A triangle in which two sides are given parallel
Required:
To show both triangle equal
Explanation:
[tex]\begin{gathered} DB\parallel\frac{1}{EA} \\ \\ m\angle CDB=m\angle CEA \\ m\angle CBD=m\angle CEA \\ m\angle C=m\angle C \\ \Delta CDB\approx\Delta CEA \end{gathered}[/tex]
Required answer:
Above prove
