Respuesta :

[tex]3\frac{1}{2}x-4\frac{1}{10}-(\frac{3}{8}x+2\frac{1}{5})[/tex]

To solve this:

Write the mixed numbers as fractions

[tex]a\frac{b}{c}=\frac{ac+b}{c}[/tex][tex]\begin{gathered} 3+\frac{1}{2}=\frac{6+1}{2}=\frac{7}{2} \\ \\ 4\frac{1}{10}=\frac{40+1}{10}=\frac{41}{10} \\ \\ 2\frac{1}{5}=\frac{10+1}{5}=\frac{11}{5} \end{gathered}[/tex]

You get:

[tex]=\frac{7}{2}x-\frac{41}{10}-\frac{3}{8}x-\frac{11}{5}[/tex]

Combine like terms:

[tex]\begin{gathered} \frac{7}{2}x-\frac{3}{8}x=\frac{56x+6x}{16}=\frac{62}{16}x=\frac{31}{8}x \\ \\ -\frac{41}{10}-\frac{11}{5}=\frac{-205-110}{50}=-\frac{315}{50}=-\frac{63}{10} \\ \\ \\ =\frac{31}{8}x-\frac{63}{10} \end{gathered}[/tex]

Turn fractions into mixed numbers:

[tex]\begin{gathered} \frac{31}{8}=\frac{24}{8}+\frac{7}{8}=3\frac{7}{8} \\ \\ \frac{63}{10}=\frac{60}{10}+\frac{3}{10}=6\frac{3}{10} \end{gathered}[/tex]You get as final result:[tex]3\frac{7}{8}x-6\frac{3}{10}[/tex]

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