Triangle ABC is similar triangle DEF. Find the necessary of side FD. Round your answer to the nearest tenth

SOLUTION
Step 1 :
In this question, we are given that :
Triangle ABC is similar to Triangle DEF.
We are meant to find the necessary of side FD.
Step 2 :
Using the principles of Similar Triangles, we have that:
[tex]\frac{FD}{CA}\text{ = }\frac{EF}{BC}[/tex]where:
[tex]\begin{gathered} FD\text{ = ?} \\ CA\text{ = 49} \\ EF\text{ = 5} \\ BC\text{ = 23} \end{gathered}[/tex][tex]\frac{FD}{49}\text{ = }\frac{5}{23}[/tex]Cross- multiply, we have that:
[tex]\begin{gathered} FD\text{ = }\frac{49\text{ X 5}}{23} \\ FD\text{ = }\frac{245}{23} \\ FD\text{ = 10. 65 } \\ FD\text{ = 10. 7 ( to the nearest tenth)} \end{gathered}[/tex]CONCLUSION:
The length of FD = 10. 7 ( to the nearest tenth).