Answer:
[tex]9\times10^{-4}\text{ meters}[/tex]Explanation:
The diameter of the virus is given below:
[tex]1.8\times10^{-6}[/tex]The microscope is set so that the object appears 5 x 10² times larger than its actual size.
Therefore, the diameter of the virus when viewed under the mīcroscope is:
[tex]\begin{gathered} =5\times10^2\times\text{Actual Size} \\ =5\times10^2\times1.8\times10^{-6} \end{gathered}[/tex]We then simplify our result by collecting like terms.
[tex]\begin{gathered} =5\times1.8\times10^2\times10^{-6} \\ =9\times10^{2+(-6)} \\ =9\times10^{2-6} \\ =9\times10^{-4}\text{ meters} \end{gathered}[/tex]