Question

Solve the trianglea= 1200 in , b= 859 in, c= 956 in

Answer 1

Given:

Sides of triangle a = 1200, b =859, c = 956.

Required:

Angles of a triangle.

Explanation:

We know that

$\begin{gathered} CosA=\frac{b^2+c^2-a^2}{2bc} \\ CosB=\frac{a^2+c^2-b^2}{2ac} \\ CosC=\frac{a^2+b^2-c^2}{2ab} \end{gathered}$

Now,

$\begin{gathered} CosA=\frac{859^2+956^2-1200^2}{2\times859\times956} \\ CosA=\frac{737881+913936-1440000}{1642408} \\ A=Cos^{-1}(0.13) \end{gathered}$

And

$\begin{gathered} CosB=\frac{1200^2+956^2-859^2}{2\times1200\times956} \\ CosB=\frac{1440000+913936-737881}{2294400} \\ A=Cos^{-1}(0.14) \end{gathered}$

And

$\begin{gathered} CosC=\frac{1440000+737881-913936}{2\times1200\times859} \\ C=Cos^{-1}(0.61) \end{gathered}$

Answer:T

These are three angles of triangle.