Question

s(2) = 62+1Find (1) (2). Include any restrictions on the domainOA () (-)==*-6OB () (z) 2,24006 (1) (z) = 0,220OD (1) (z) = 27-SUBMIT

Answer 1

We have

$\begin{gathered} f(x)=\sqrt[3]{4x} \\ g(x)=6x \end{gathered}$

so

$(\frac{f}{g})(x)=\frac{\sqrt[3]{4x}}{6x+1}$

the restriction is not divided between 0

6x+1=0

6x=-1

x=-1/6

so our restriction is

$x\ne-\frac{1}{6}$

so the correct answer is D.