Question

The weak ionization constant (Ka)for HCO3 is equal to:AB[H3O+][CO32- ](HCO3-)[HCO3 -[H3O+][CO32-]

Answer 1

Answer

A

$\frac{\lbrack H_3O^+\rbrack)(\lbrack C(O_3)^2\rbrack}{\lbrack HCO_3^-\rbrack}$

Explanation

The ionization of HCO₃⁻ in H₂O is:

$HCO₃⁻+H₂O\rightleftarrows H_3O^++CO₃^{2-}$

The general ionization constant, Ka is given as:

$Ka=\frac{\lbrack Products\rbrack}{\lbrack Reactants\rbrack}$

Hence, the ionization (Ka) of HCO₃⁻ is equal to:

$\frac{\lbrack H_3O^+\rbrack\lbrack CO_3^{2-}\rbrack}{\lbrack HCO_3^-\rbrack}$

Option A is the correct answer.