Given the diagram below, what is sin (30°) ?O A.OB.O C.OD. /3141411260°930°Triangle not drawn to scale

Solution:
Given:
Using the trigonometric identity of sine;
[tex]\begin{gathered} sin\theta=\frac{opposite}{hypotenuse} \\ where: \\ opposite=x \\ hypotenuse=9 \\ \theta=30^0 \\ \\ Hence, \\ sin30=\frac{x}{9} \\ From\text{ trigonometric tables;} \\ sin30=\frac{1}{2} \\ Hence, \\ \frac{1}{2}=\frac{x}{9} \\ Cross\text{ multiplying;} \\ 2x=9 \\ Dividing\text{ both sides by 2,} \\ x=\frac{9}{2} \end{gathered}[/tex]Hence, the value of sin 30 is;
[tex]\begin{gathered} sin(30^0)=\frac{opposite}{hypotenuse} \\ sin(30^0)=\frac{x}{9} \\ But\text{ }x=\frac{9}{2} \\ Thus; \\ sin(30^0)=\frac{\frac{9}{2}}{9} \\ sin(30^0)=\frac{9}{2}\div9 \\ sin(30^0)=\frac{9}{2}\times\frac{1}{9}=\frac{9}{18} \\ sin(30^0)=\frac{1}{2} \end{gathered}[/tex]Therefore,
[tex]sin(30^0)=\frac{1}{2}[/tex]The correct answer is OPTION B.