Question

A plane rises from take-off andflies at an angle of 18with thehorizontal runway. When it hasgained 200 feet, find thedistance that the plane hasflown.

Answer 1

Answer:

647 ft

Explanation:

Given the below figure;

To determine the value c, we have to take the sine of angle 18 degrees as seen below;

$\begin{gathered} \sin18=\frac{opposit\text{e side to angle 18}}{hypotenuse\text{ to angle 18}}=\frac{200}{c} \\ \sin18=\frac{200}{c} \end{gathered}$

Let's cross multiply;

$c*\sin18=200$

Let's divide both sides by sin 18;

$\begin{gathered} \frac{c*\sin18}{\sin18}=\frac{200}{\sin18} \\ c=\frac{200}{\sin18} \\ c=647ft \end{gathered}$

So the distance the plane has flown is 647 ft