Respuesta :

ANSWER

[tex]e^x\text{ + }\frac{1}{3}\ln (|x|)\text{ + C}[/tex]

EXPLANATION

Given:

[tex]\int (e^x\text{ + }\frac{1}{3x})dx[/tex]

Integrating the expression:

[tex]\begin{gathered} =\int (e^x)\text{ }dx\text{+}\int (\frac{1}{3x})dx \\ =\text{ }e^x\text{ + }\frac{1}{3}\int (\frac{1}{x})dx\text{ + c} \\ =e^x\text{ + }\frac{1}{3}\ln \text{ (|x|) + C} \end{gathered}[/tex]

RELAXING NOICE
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