Question

18 - 5z + 6z > 3 + 6

Answer 1

The given expression is

$18-5z+6z>3+6$

First, we reduce like terms.

$18+z>9$

Then, we subtract 18 on each side.

$\begin{gathered} 18+z-18>9-18 \\ z>-9 \end{gathered}$

Therefore, the solution is all real numbers greater than -9.