The amount of calories burnt in t mins in Routine #1 is given by:
[tex]20+18.5t[/tex]The amount of calories burnt in t mins in Routine #2 is given by:
[tex]46+13.3t[/tex]For the time period when the amounts of time spent running in Routine #1 burn fewer calories than Routine #2, we have:
[tex]\begin{gathered} 20+18.5t\lt46+13.3t \\ \text{ Subtract }13.3t\text{ from both sides of the equation:} \\ 20+18.5t-13.3t\lt46+13.3t-13.3t \\ 20+5.2t\lt46 \\ \text{ Subtract }20\text{ from both sides of the equation:} \\ 20-20+5.2t\lt46-20 \\ 5.2t\lt26 \\ \text{ Dividing both sides by }5.2 \\ t\lt\frac{26}{5.2}=5 \\ t\lt5 \end{gathered}[/tex]Since t is non-negative, it follow that the solution is given by:
0 ≤ t ≤ 5
.