Answer:
The axis of symmetry is x = -2
The vertex is (-2, 5)
Explanation:
For a quadratic equation of the form:
[tex]y=ax^2+bx+c[/tex]
The formula for the axis of symmetry is:
[tex]A_{symmetry}=-\frac{b}{2a}[/tex]
In this case, a = -1 and b = -4
Thus:
[tex]A_{symmetry}=-\frac{-4}{2(-1)}=-\frac{4}{2}=-2[/tex]
Thus, the axis of symmetry is x = -2
To find the vertex, we need to find the value of y in the axis of symmetry. Then, we need to evaluate the equation for x = -2:
[tex]y=-(-2)^2-4(-2)+1=-4+8+1=5[/tex]
The vertex is (-2, 5)
