Find the surface area and volume of the solid given.

Answer:
• Surface Area= 121.2 cm²
,• Volume = 51.46 cm³
Explanation:
The solid is in the shape of a Right-triangular Prism.
The following are the dimensions of the shapes present.
0. Two right triangles with a base of 6.2cm and a height of 8.3cm.
,1. A rectangle with dimension 6.2 cm by 2.8cm
,2. A rectangle with dimension 8.3 cm by 2.8cm
,3. A rectangle with dimension 10.4 cm by 2.8cm
Surface Area
[tex]\begin{gathered} \text{Surface Area}=2(\text{Area of Triangle)+Area of the 3 rectangles} \\ =2(\frac{1}{2}\times6.2\times8.3)+(6.2\times2.8)+(8.3\times2.8)+(10.4\times2.8) \\ =51.46+17.36+23.24+29.12 \\ =121.18\operatorname{cm}^2 \\ \approx121.2\operatorname{cm}^2 \end{gathered}[/tex]Volume
The cross-section of the solid is a right triangle.
[tex]\begin{gathered} \text{Volume}=\text{Area of cross-section }\times Length \\ =\frac{1}{2}bh\times\text{Length} \\ =(\frac{1}{2}\times6.2\times8.3)\times2 \\ =51.46\operatorname{cm}^3 \end{gathered}[/tex]