The sum of n and 4 can be express as:
[tex]n+4[/tex]Three times this sum is:
[tex]3(n+4)[/tex]And this is equal to 12, then:
[tex]3(n+4)=12[/tex]Solving for n, we have:
[tex]\begin{gathered} 3(n+4)=12 \\ 3n+12=12 \\ 3n=12-12 \\ 3n=0 \\ n=\frac{0}{3} \\ n=0 \end{gathered}[/tex]Therefore, n=0.
