Given the following question:
[tex]9\frac{2}{5}-5\frac{3}{6}[/tex][tex]\begin{gathered} 9\frac{2}{5}-5\frac{3}{6} \\ 9\frac{2}{5}=5\times9=45+2=47=\frac{47}{5} \\ 5\frac{3}{6}=6\times5=30+3=33=\frac{33}{6} \\ \frac{47}{5}-\frac{33}{6} \\ CD=30 \\ \frac{47}{5}\times6=\frac{282}{30} \\ \frac{33}{6}\times5=\frac{165}{30} \\ \frac{282}{30}-\frac{165}{30} \\ 282-165=117=\frac{117}{30}=\frac{39}{10} \\ \text{ Convert into mixed number} \\ \frac{39}{10}=39\div10=3\frac{9}{10} \\ =3\frac{9}{10} \end{gathered}[/tex]Your answer is 3 9/10
