Given the inequality;
[tex]-16\leq\frac{8}{3}t[/tex]Firstly, let us multiply both sides by 3;
[tex]\begin{gathered} -16\times3\leq3\times\frac{8}{3}t \\ -48\leq8t \end{gathered}[/tex]Then let us divide both sides by 8;
[tex]\begin{gathered} \frac{-48}{8}\leq\frac{8t}{8} \\ -6\leq t \\ t\ge-6 \end{gathered}[/tex]Therefore, the solution to the inequality is;
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