When we subtract two logarithms with the same base, we can write it as a single logarithm:
[tex]\log _ax-\log _ay=\log _a\frac{x}{y}[/tex]In this problem, we have:
a = 3
x = 60
y = 10
Using those values in the above identity, we find:
[tex]\begin{gathered} \log _360-\log _310=\log _3\frac{60}{10} \\ \\ =\log _36 \end{gathered}[/tex]Therefore, the answer is:
[tex]\log _36[/tex]