Question

For the standard normal distribution shown on the right, find the probability of z occurring in the indicated region.

Answer 1

From the graph, the z-score is -1.91, and the probability we are looking for is:

$P(z>-1.91)=1-P(z\le-1.91)$

From tables, we know that:

$P(z\le-1.91)=0.028067$

Then:

$\begin{gathered} P(z>-1.91)=1-0.028067 \\ \therefore P(z>-1.91)=0.971933 \end{gathered}$

The probability is 0.971933