SOLUTION
The given points are:
[tex]P(-8,3),Q(6,5)[/tex]
Recall the distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the distance formula, the distance between P and Q is:
[tex]\begin{gathered} d=\sqrt{(6-(-8))^2+(5-3)^2} \\ d=\sqrt{14^2+2^2} \\ d=\sqrt{200} \\ d=14.14 \end{gathered}[/tex]
Therefore the distance between P and Q is about 14.14
Recall the midpoint formula:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
Using the midpoint formula, the midpoint of P and Q is:
[tex]\begin{gathered} (\frac{-8+6}{2},\frac{3+5}{2}) \\ =(\frac{-2}{2},\frac{8}{2}) \\ =(-1,4) \end{gathered}[/tex]
Therefore the midpoint of P and Q is (-1,4).
