The given situation is modeled by the following formula
[tex]A_{\text{vertex}}=r^2\cdot A_{base}[/tex]Where r = 5/h, then
[tex]\begin{gathered} 25=(\frac{5}{h})^2\cdot36 \\ 25=\frac{25}{h^2}\cdot36 \\ h^2=\frac{25}{25}\cdot36 \\ h=\sqrt[]{36} \\ h=6 \end{gathered}[/tex]